Checking a matrix for duplicates in specific row, removing the respective columns

1 view (last 30 days)
So, I try to explain this.
I have a two-row matrix of values, [x;y], f.e.
x=[1 2 2 3 4 5 6 6 7]
y=[1 2 3 4 5 6 7 7 8]
being merged into the matrix:
d= [1 2 2 3 4 5 6 6 7;
1 2 3 4 5 6 7 7 8]
I then want to check this matrix for repeats in the first row & remove the respective columns, while saving the x values of the columns being removed as a seperate vector. So Output should be something like:
d=[1 3 4 5 7;
1 3 4 5 8]
x_cut=[2 6]
It should be noted that this would have to scan for multiple repeats of different values, as shown above.
Thank you.
Have a great day & stay safe
Claudius Appel

Accepted Answer

Bruno Luong
Bruno Luong on 6 Aug 2020
Edited: Bruno Luong on 6 Aug 2020
d= [1 2 2 3 4 5 6 6 7;
1 2 3 4 5 6 7 7 8]
dd = diff([nan,d(1,:),nan])==0;
remove = dd(1:end-1) | dd(2:end)
x_cut = unique(d(1,remove),'stable')
d(:,remove) = []
  3 Comments

Sign in to comment.

More Answers (0)

Categories

Find more on Numerical Integration and Differential Equations in Help Center and File Exchange

Products


Release

R2020a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!