help for get an output in form of table

hi

i have this code for blasius equation and want to get an output in form of a table like the picture.

Can anyone write the code?

the equation is 2f'''+ff''=0

the code is:

clc

clear all

close all

%% Parameters of Blasius Equation

U_inf = 1;

L = 10;

mu = 1.789E-5;

rho = 1.225;

nu = mu/rho;

A = sqrt(nu/U_inf);

h = 0.01;

%% Numerical Solution of Blasius Equation Using Runge-Kutta

f1 = @(x, y1, y2, y3) y2;

f2 = @(x, y1, y2, y3) y3;

f3 = @(x, y1, y2, y3) -y1*y3;

eta = 0:h:10;

x = 0:h:10;

y1(1) = 0;

y2(1) = 0;

y3(1) = 0.4696;

for i = 1:(length(eta)-1)

a = h.*[f1(eta(i), y1(i), y2(i), y3(i)), f2(eta(i), y1(i), y2(i), y3(i)), f3(eta(i), y1(i), y2(i), y3(i))];

b = h.*[f1(eta(i), y1(i)+a(1)/2, y2(i)+a(2)/2, y3(i)+a(3)/2), f2(eta(i)+h/2, y1(i)+a(1)/2, y2(i)+a(2)/2, y3(i)+a(3)/2), f3(eta(i)+h/2, y1(i)+a(1)/2, y2(i)+a(2)/2, y3(i)+a(3)/2)];

c = h.*[f1(eta(i), y1(i)+b(1)/2, y2(i)+b(2)/2, y3(i)+b(3)/2), f2(eta(i)+h/2, y1(i)+b(1)/2, y2(i)+b(2)/2, y3(i)+b(3)/2), f3(eta(i)+h/2, y1(i)+b(1)/2, y2(i)+b(2)/2, y3(i)+b(3)/2)];

d = h.*[f1(eta(i), y1(i)+c(1), y2(i)+c(2), y3(i)+c(3)), f2(eta(i)+h, y1(i)+c(1), y2(i)+c(2), y3(i)+c(3)), f3(eta(i)+h, y1(i)+c(1), y2(i)+c(2), y3(i)+c(3))];

y3(i+1) = y3(i)+ 1/6*(a(3)+2*b(3)+2*c(3)+d(3));

y2(i+1) = y2(i)+ 1/6*(a(2)+2*b(2)+2*c(2)+d(2));

y1(i+1) = y1(i)+ 1/6*(a(1)+2*b(1)+2*c(1)+d(1));

end