Nonlinear system of equations
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I am trying to solve a system of nonlinear equations. I am not sure what method is the best to use for my problem but using syms does not seem to work. How do I get a numerical solution to the following system of equations?
clear
b1=1000;
b2=100;
c=50;
t=0.76;
T=950;
n=5;
syms sum R1 R2 R3 R4 R5
eq1=(R1-R2)-((1+t)*T*(R2^t-R1^t)+50)/b2 ==0;
eq2=(R2-R3)-((1+t)*T*(R3^t-R2^t)+50)/b2 ==0;
eq3=(R3-R4)-((1+t)*T*(R4^t-R3^t)+50)/b2 ==0;
eq4=(R4-R5)-((1+t)*T*(R5^t-R4^t)+50)/b2 ==0;
eq5=sum-(n*R5+(R4-R5)+2*(R3-R4)+3*(R2-R3)+4*(R1-R2)) ==0;
eq6=R1-(b1-b2*sum-(1+t)*T*R1^t-c)/b2 ==0;
eq7=R2-(b1-b2*sum-(1+t)*T*R2^t-2*c)/b2 ==0;
eq8=R3-(b1-b2*sum-(1+t)*T*R3^t-3*c)/b2 ==0;
eq9=R4-(b1-b2*sum-(1+t)*T*R4^t-4*c)/b2 ==0;
eq10=R5-(b1-b2*sum-(1+t)*T*R5^t-5*c)/b2 ==0;
sol=solve(eq1, eq2, eq3, eq4, eq5, eq6, eq7, eq8, eq9, eq10);
sol;
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Accepted Answer
Stephan
on 27 May 2020
Edited: Stephan
on 27 May 2020
function myEq
b1=1000;
b2=100;
c=50;
t=0.76;
T=950;
n=5;
x0 = [1 1 1 1 1 1];
opts = optimoptions('fsolve', 'Algorithm', 'levenberg-marquardt');
sol = fsolve(@fun, x0, opts)
test = fun(sol)
function eq = fun(x)
Sum = x(1);
R1 = x(2);
R2 = x(3);
R3 = x(4);
R4 = x(5);
R5 = x(6);
eq(1)=(R1-R2)-((1+t)*T*(R2^t-R1^t)+50)/b2;
eq(2)=(R2-R3)-((1+t)*T*(R3^t-R2^t)+50)/b2;
eq(3)=(R3-R4)-((1+t)*T*(R4^t-R3^t)+50)/b2;
eq(4)=(R4-R5)-((1+t)*T*(R5^t-R4^t)+50)/b2;
eq(5)=Sum-(n*R5+(R4-R5)+2*(R3-R4)+3*(R2-R3)+4*(R1-R2));
eq(6)=R1-(b1-b2*Sum-(1+t)*T*R1^t-c)/b2;
eq(7)=R2-(b1-b2*Sum-(1+t)*T*R2^t-2*c)/b2;
eq(8)=R3-(b1-b2*Sum-(1+t)*T*R3^t-3*c)/b2;
eq(9)=R4-(b1-b2*Sum-(1+t)*T*R4^t-4*c)/b2;
eq(10)=R5-(b1-b2*Sum-(1+t)*T*R5^t-5*c)/b2;
end
end
gives acceptabe results:
Equation solved.
fsolve completed because the vector of function values is near zero
as measured by the value of the function tolerance, and
the problem appears regular as measured by the gradient.
<stopping criteria details>
sol =
1.5076 0.3566 0.3279 0.2998 0.2722 0.2453
test =
1.0e-09 *
Columns 1 through 9
-0.0108 -0.0043 0.0059 0.1264 -0.0998 -0.0157 -0.0049 -0.0006 -0.0065
Column 10
-0.1329
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