I have 3 outputs but the scope shows 20 outputs

function [p, v, a]=findit(theta_dot)
    r = 120*10^-3;
    c = 250*10^-3;
    
    t = 0:0.001:(60/500);
    theta = theta_dot*t;
    
    d1 = r*cos(theta); 
    h = r*sin(theta);
    d2 = (c.^2-h.^2).^(1/2);
    
    p = d1 + d2;
    v = -r.*theta_dot.*sin(theta)-(r.^2.*theta_dot.*sin(2.*theta))./(2*(c.^2-r.^2.*sin(theta).^2)).^(3/2);
    a = -r.*theta_dot.^2.*cos(theta)-(4*r.^2.*theta_dot.^2.*cos(2.*theta).*(c.^2-r.^2.*sin(theta).^2)+(r.^2.*theta_dot*sin(2.*theta).^2))/(4*(c.^2-r.^2.*sin(theta).^2).^(3/2));
    v = v * 100;
    a = a * 100;

I give 500*2*pi/60 to input of function.

[Meddour Aissam riad]

Can you send me the file i'll check it for you

[jessupj]

just a though: the horizontal axis of the scope is usually 'time', but it doesn't look like you have any time dependence other than within the function. perhaps it's graphing your 3-value timeseries as [3*time] constants?

[furkan mola]

thanks for your answers. i solved problem with Ameer Hamza's model. i tried with clock block before but the resolution was not good. so i tried this way.

Answer 1

[Ameer Hamza]

It is not displaying 20 signals. In fact, it is displaying 121*3=363 signals.

That is not the correct way to define time-dependent signals in Simulink. Check the attached file (saved in R2019a) to see how to create those signals in Simulink correctly.

[furkan mola]

thank you for your interest. i have tried clock block with product block for ;

theta = theta_dot*t;

but the resolution was not good and i could not fix. now, i tried your model and i got the same result. but i have set decimation = 100 in your model and i solve all problems. thanks a lot.

[Ameer Hamza]

I am glad to be of help.