I want to count the number of times each event (a, b, c... up until j) occurs, a(t<1 hour) b(1 hour<t<2 hours) c(2 hours<t<3 hours)... up to j( t>9 hours) based on the following sample in order to find the probability of any individual event occuring

3 views (last 30 days)
'02:47:09'
'03:28:26'
'13:57:18'
'08:58:46'
'10:31:50'
'11:03:35'
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'01:37:30'
'04:38:33'
'03:02:50'
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'03:47:08'
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'04:57:18'
'03:47:12'
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'03:28:25'
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'03:47:26'
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'05:46:56'
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Accepted Answer

David Hill
David Hill on 9 Jan 2020
If your data is not in a cell array, convert to a cell array. For example:
A={'02:47:09';'03:28:26';'13:57:18';'08:58:46';'10:31:50'};
A=hours(duration(A));
a=nnz(A<1);
b=nnz(A>=1&A<2);
c=nnz(A>=2&A<3);
d=nnz(A>=3&A<4);
e=nnz(A>=4&A<5);
f=nnz(A>=5&A<6);
g=nnz(A>=6&A<7);
h=nnz(A>=7&A<8);
i=nnz(A>=8&A<9);
j=nnz(A>=9);

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