Can I draw the figure with the help of MATLAB code ?

4 views (last 30 days)
I want to figure out the following graph to show map between two annular region as follows:
image 1.jpg
Here B is subset of A and we want to show the map from (A - B) to B.
How do I plot this graph?
Can I draw the figure with the help of MATLAB code or Mathematica ?
In that case what would be the Matlab Code ?
Help me

Accepted Answer

Star Strider
Star Strider on 28 Aug 2019
Try this:
circx = @(r,a) r.*cos(a);
circy = @(r,a) r.*sin(a);
a = linspace(0, 2*pi);
fill(0.2*circx(1,a)-0.5, 0.2*circy(1,a), 'g')
hold on
fill(0.1*circx(1,a)-0.5, 0.1*circy(1,a), 'w')
fill(0.2*circx(1,a)+0.5, 0.2*circy(1,a), 'g')
fill(0.1*circx(1,a)+0.5, 0.1*circy(1,a), 'w')
hold off
axis equal
xlim([-1 1])
annotation('textarrow',[0.35, 0.7], [0.58, 0.58])
text(-0.6, 0.15, 'A-B')
text([-0.5 0.5], [0 0], 'B', 'HorizontalAlignment','center')
text(0, 0.2, '\itf\rm', 'FontSize',15)
Experiment to get the result you want.
Can I draw the figure with the help of MATLAB code - 2019 08 28.png
Mabud Sarkar
Mabud Sarkar on 20 Aug 2020
Edited: Mabud Sarkar on 20 Aug 2020
In your 1st answer, you used
text([-0.5 0.5], [0 0], 'B', 'HorizontalAlignment','center')
Why did you use both [-0.5 0.5] and [0 0] ?
But in the previous line you used only
text(-0.6, 0.15, 'A-B')
Can you please explain the above ?
Second question,
why in case of annotation textarrow, we are allowed only points between 0 and 1 ?
Why not negative points ?
Star Strider
Star Strider on 20 Aug 2020
They are two separate text calls displaying two different strings.
The ‘B’ is displayed twice, once in each circle, so two positions, one for each. (I could have used two different text calls. Using one text call with two coordinates is more efficient.)
The ‘A-B’ is displayed once, so it only needs one set of coordinates.

Sign in to comment.

More Answers (2)

KALYAN ACHARJYA on 28 Aug 2019
Edited: KALYAN ACHARJYA on 28 Aug 2019
Please note: I have done the Jugaad here. I have no idea what the plot represents?
I tried it for 10 minutes, hence I posted it as 2nd answer.
for i=1:4
y_circle = r(i)*sin(theta)+y(i);
if r(i)==max(r)
hold on;
  1 Comment
Mabud Sarkar
Mabud Sarkar on 28 Aug 2019
Edited: Mabud Sarkar on 28 Aug 2019
Thank you for your answer. But how the arrow will touch the circle B ?
Actually this figures represnts mapping between two annular region in Complex analysis of M.Sc. mathematics ?

Sign in to comment.

Steven Lord
Steven Lord on 28 Aug 2019
A regular N-sided polygon (for large N) is visually indistinguishable from a circle. Try:
>> A = nsidedpoly(1000, 'Center', [0 0], 'Radius', 2);
>> B = nsidedpoly(1000, 'Center', [0 0], 'Radius', 1);
>> C = subtract(A, B);
>> plot(C, 'FaceColor', 'g')
>> axis equal
To make copies of the polyshape objects A and B at a different location, call translate on them (specifying a different variable name as output.) See this documentation page for more functions that you can use to operate on polyshape objects.
For the arrow, call annotation. For the letters, call text.
  1 Comment
Mabud Sarkar
Mabud Sarkar on 28 Aug 2019
Please add the rest code because I can not get it at the beginning. However I will grasp the code for future. So please add the complete code with the figure.

Sign in to comment.


Find more on 2-D and 3-D Plots in Help Center and File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!