Use ./ or / in symbolic expressions. Doesn't make a difference?

>> syms k
>> f = k./(k+1)

f =

k/(k + 1)

>> g = k/(k+1)

g =

k/(k + 1)

f and g above end up being the same. Why?

Answer 1

[Walter Roberson]

The operators are overloaded in symbolic expressions and defined to mean the same thing for symbolic expressions.

MuPAD's / operator is sensitive to the data type that is being used and only does matrix arithmetic when appropriate. See http://www.mathworks.com/help/toolbox/mupad/linalg/index.html