How to create a random number that is a percent of each element in a vector

24 views (last 30 days)
I was wondering if anybody could solve this simple roulette indexing/random number question i've been struggling with for a long time. In the for loop I need to create a variable Bet that is a random number that is between 2-12% of each value in row 1 of RoulettePlayers. I commented where I need to include this. Any help is appreciated I've been trying to figure this out for hours.
RouletteRounds = 10 %number of rounds
RoulettePlayers = zeros(RouletteRounds+1,RouletteRounds);
initial_intt = randi([5000,25000],1,10); %randomly generates initial integer value for in pocket $
RoulettePlayers(1,:) = initial_int %makes row 1 of RouletteRounds equal to in pocket cash
BetType = zeros(3,10); %ignore this
for l = 1:RouletteRounds
Bet = randi(1,RoulettePlayers) %<- here i need to create a random number that is between 2-12% of the inidivduals in pocket cash (so row 1 of Roulette Players)

Accepted Answer

Kevin Phung
Kevin Phung on 25 Feb 2019
Edited: Kevin Phung on 25 Feb 2019
here's a small example:
a = [100 200 300 400 500; 600 700 800 900 1000]
bet = [];
for i = 1:size(a,2) %for the number of columns,
%append a value from 2-12% for each element in the first row
bet(end+1) = randi([.02*a(1,i) .12*a(1,i)]); %randi generates an random integer from [min max]

More Answers (0)


Find more on Number games in Help Center and File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!