Get row no by which the other row is less

hey

I have following cell array which is obtained by comparison of row's elements (if column element of row1 is less than row2 than result is 1 otherwise 0). Row is considered as less if all elements of that row are 1. Now I want to get the element by which that row is less. For example if row2 is less than row1 then I want '1' as answer.

    A{1,1} =  [1,0,1,1,1,0,1,1,0;  1,1,1,1,1,1,1,1,1]

kindly help.

[Tha saliem]

In simple words if some element at row 2 is less than an element in row 1 then how can I get the row no of element by which it is less like here it is 1.

Answer 1

[Star Strider]

I am not certain what you are asking, since there appear to be two different requests.

Try this:

A{1,1} =  [1,0,1,1,1,0,1,1,0;  1,1,1,1,1,1,1,1,1];

AllColumnsLess = cellfun(@(x) all(x,2), A, 'UniformOutput',false)
AllCols = [AllColumnsLess{:}]

[FindRowsLessThan,FindColsLessThan] = cellfun(@find, A', 'UniformOutput',false)
FindRows = [FindRowsLessThan{:}]
FindCols = [FindColsLessThan{:}]

The ‘AllColumnsLess’ returns 1 if the condition is true for all elements in the vector (defined here as row vectors).

The find call returns the row and column indices for the non-zero elements in ‘A’. See the documentation for the find and all functions for details on how they work and what outputs they return.

[Tha saliem]

Hey Thank You so much for your helping. I got the idea of doing it.

[Star Strider]

As always, my pleasure!