Finding a row with a certain condition

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Assume I have the following matrix.
733458 91 1.01510000000000 1.01680000000000 1.01490000000000 1.01520000000000 1.01585000000000
733458 112 1.01620000000000 1.01620000000000 1.01400000000000 1.01610000000000 1.01510000000000
733458 135 1.01440000000000 1.01540000000000 1.01430000000000 1.01480000000000 1.01485000000000
733458 154 1.01420000000000 1.01580000000000 1.01410000000000 1.01420000000000 1.01495000000000
733458 173 1.01550000000000 1.01570000000000 1.01490000000000 1.01560000000000 1.01530000000000
I want to find the row that contains in column one the value 733458 and that is the closest to 158 in column 2. How can I do that?

Accepted Answer

Azzi Abdelmalek
Azzi Abdelmalek on 22 Jun 2016
A=[733458 91 1.01510000000000 1.01680000000000 1.01490000000000 1.01520000000000 1.01585000000000
733458 112 1.01620000000000 1.01620000000000 1.01400000000000 1.01610000000000 1.01510000000000
733458 135 1.01440000000000 1.01540000000000 1.01430000000000 1.01480000000000 1.01485000000000
733458 154 1.01420000000000 1.01580000000000 1.01410000000000 1.01420000000000 1.01495000000000
733459 173 1.01550000000000 1.01570000000000 1.01490000000000 1.01560000000000 1.01530000000000]
ii=ismember(A(:,1),733458)
B=A(ii,:)
[~,jj]=min(abs(A(ii,2)-158))
out=B(jj,:)

More Answers (1)

Star Strider
Star Strider on 22 Jun 2016
One approach:
x = 158;
idx = find((M(:,1) == 733458) & ((x-M(:,2)).^2) == min( (x-M(:,2)).^2));
idx =
4

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