plot based on if and else condition

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Malar Vizhi
Malar Vizhi on 14 Aug 2022
Commented: Malar Vizhi on 16 Aug 2022
GoodEvening Sir/Mam,
I'm working in intesity of speech .I have classified it based om maximum to minimum energy but i dont know how to plot them.Please help me as possible
[x,fs] = audioread("sa.wav");
%end
si = 0.020;Fsi=si*fs;t=(0:1/Fsi);
frames=framing(x,fs,Fsi);
[r,c] = size(frames);
signal = zeros(size(0));
for i = 1:r
signal(i) = sum(frames(i,:).^2);
end
A=zeros(1,length(signal));
B=zeros(1,length(signal));
C=zeros(1,length(signal));
D=zeros(1,length(signal));
sig = max(signal);
for j=1:length(signal)
I(j)=(signal(j)/sig);
if(0.9<=I(j)<=1)
A(j)=I(j);
plot(A,'b-');hold on
elseif(0.6<=I(j)<=0.8)
A(j)=I(j);
plot(A,'b-');hold on
elseif(0.4<I(j)<=0.6)
A(j)=I(j);
plot(A,'b-');hold on
elseif(0.2<=I(j)<=0.5)
A(j)=I(j);
plot(A,'b-');hold on
elseif(0<=I(j)<=0.1)
A(j)=I(j);
plot(A,'b-');hold on
end
end

Answers (4)

Torsten
Torsten on 14 Aug 2022
MATLAB does not accept "double inequalities".
Thus instead of
if a < b < c
you will have to use
if a < b && b < c
Further, you should plot A completely after the if-clause, not after every value of j.
Further, you missed to classify the cases 0.8 < l(j) < 0.9, 0.4 < l(j) < 0.5 and 0.1 < l(j) < 0.2. Or should A remain 0 in these cases ?
  3 Comments
Torsten
Torsten on 14 Aug 2022
I can't answer anything useful without the modified code ...

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Malar Vizhi
Malar Vizhi on 14 Aug 2022
[x,fs] = audioread("sa.wav");
%end
si = 0.020;Fsi=si*fs;t=(0:1/Fsi);
frames=framing(x,fs,Fsi);
[r,c] = size(frames);
signal = zeros(size(0));
for i = 1:r
signal(i) = sum(frames(i,:).^2);
end
%
% plot(signal,'bo');
A=zeros(1,length(signal));
B=zeros(1,length(signal));
C=zeros(1,length(signal));
D=zeros(1,length(signal));
sig = max(signal);
for j=1:length(signal)
I(j)=(signal(j)/sig);
if(0.9<=I(j)) && (I(j)<=1)
A(j)=I(j);
plot(A,'b-');hold on
elseif(0.6<=I(j)) && (I(j)<=0.9)
A(j)=I(j);
plot(A,'b-');hold on
elseif(0.4<I(j)) && (I(j)<=0.6)
A(j)=I(j);
plot(A,'b-');hold on
elseif(0.2<=I(j)) && (I(j)<=0.4)
A(j)=I(j);
plot(A,'b-');hold on
elseif(0<=I(j))&& (I(j)<=0.2)
A(j)=I(j);
plot(A,'b-');
end
end

Malar Vizhi
Malar Vizhi on 14 Aug 2022
If i give plot outside i got the output as same as signal
[x,fs] = audioread("sa.wav");
%end
si = 0.020;Fsi=si*fs;t=(0:1/Fsi);
frames=framing(x,fs,Fsi);
[r,c] = size(frames);
signal = zeros(size(0));
for i = 1:r
signal(i) = sum(frames(i,:).^2);
end
%
% plot(signal,'bo');
A=zeros(1,length(signal));
B=zeros(1,length(signal));
C=zeros(1,length(signal));
D=zeros(1,length(signal));
sig = max(signal);
for j=1:length(signal)
I(j)=(signal(j)/sig);
if(0.9<=I(j)) && (I(j)<=1)
A(j)=I(j);
% plot(A,'b-');hold on
elseif(0.6<=I(j)) && (I(j)<=0.9)
A(j)=I(j);
%plot(A,'b-');hold on
elseif(0.4<I(j)) && (I(j)<=0.6)
A(j)=I(j);
% plot(A,'b-');hold on
elseif(0.2<=I(j)) && (I(j)<=0.4)
A(j)=I(j);
% plot(A,'b-');hold on
elseif(0<=I(j))&& (I(j)<=0.2)
A(j)=I(j);
end
plot(A,'b-');
end
  1 Comment
Torsten
Torsten on 14 Aug 2022
Yes, A is the signal, normalized to 1.
What else do you expect for the plot if you set
A = signal/max(signal)
(because this is what you do) ?

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Malar Vizhi
Malar Vizhi on 16 Aug 2022
Actually this is like energy detector.I want compare highest amplitude with each amplitude of signal and seperate it into region of highest and lowest. Now the plot should differentiate these regions.
  2 Comments
Malar Vizhi
Malar Vizhi on 16 Aug 2022

Thanks a lot.I will try it

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