How to extract year, month, day from character vectors?

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I have a character vector matrix (I think that's what it's called - it was obtained with cell2mat command applied to a *.csv file) which shows this when I open it (one column):
var =
'1970/01/01'
'1970/01/02'
'1970/01/03'
'1970/01/04'
'1970/01/05'
'1970/01/06'
I would like to produce a numerical matrix X with as many rows but three columns (year, month, day, respectively). I've explored numerous options, to no avail. Any suggestions?

Accepted Answer

Kevin Holly
Kevin Holly on 11 Aug 2022
Edited: Kevin Holly on 11 Aug 2022
var =['1970/01/01'
'1970/01/02'
'1970/01/03'
'1970/01/04'
'1970/01/05'
'1970/01/06']
var = 6×10 char array
'1970/01/01' '1970/01/02' '1970/01/03' '1970/01/04' '1970/01/05' '1970/01/06'
% I want to make you aware of Datetime arrays
datetime(var,'InputFormat','yyyy/MM/dd')
ans = 6×1 datetime array
01-Jan-1970 02-Jan-1970 03-Jan-1970 04-Jan-1970 05-Jan-1970 06-Jan-1970
% Here is how you can convert your data into a numerical matrix containing Year, Day, and Month columns
m = [];
for ii = 1:size(var,1)
m = [m;split(var(ii,:),"/")'];
end
X = str2double(m)
X = 6×3
1970 1 1 1970 1 2 1970 1 3 1970 1 4 1970 1 5 1970 1 6

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