I need to split a number into N parts such that the difference between each part is exponentially increasing

4 views (last 30 days)
Hi, I need to split a number into N parts, for eg. number 1058 should be divided into 6 numbers (the sum of the 6 numbers will be equal to 1058) such that the difference between the numbers is exponentially increasing.
To elaborate if the 6 numbers are [n1, n2, n3, n4, n5, n6], the numbers n2-n1, n3-n2, n4-n3, n5-n4 give an exponential function.
Thanks for your help
  1 Comment
Bruno Luong
Bruno Luong on 3 Aug 2022
Edited: Bruno Luong on 3 Aug 2022
Here is one solution
n(1)=n(2)=... = n(6) = 1058 /6
All the different are
n(k+1)-n(k) = 0 = exp(k*(-Inf)) for k = 1..., 5, so it is an exponential function wrt k

Sign in to comment.

Answers (1)

Abhishek Chakram
Abhishek Chakram on 22 Sep 2023
Hi Jyoti Mangal,
It is my understanding that you are facing difficulty in writing the code to divide a number into N parts such that difference between each part is exponentially increasing and sum of all the parts is equal to the number itself.
You can use the concept of geometric progression (GP) for it.
Here’s an example for the same:
gp_sum = 4586; % The number to be split
N = 6; % Number of parts
r = 2; % Common ratio for geometric progression
starting_number = (gp_sum * (r - 1)) / (r^N - 1); % starting number of geometric progression
split_numbers = zeros(1, N);
split_numbers(1) = starting_number;
for i = 2:N
split_numbers(i) = starting_number * r^(i-1);
end
sum(split_numbers); % Prints the sum of splited numbers that is equal to number itself
split_numbers; % Prints the splited numbers
Best Regards,
Abhishek Chakram

Categories

Find more on Mathematics in Help Center and File Exchange

Products


Release

R2021b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!