calculate the number of odd fence values instead of printing them

40 views (last 30 days)
Sample Output:
Given A = [ 5, 4, 6, 7, 3 ; 1, 2, 3, 4, 5 ; 5, 6, 4, 2, 4 ; 4, 5, 3, 2, 1]
% output demo
There are 9 odd values in the fence.
% This is my code
% given a matrix
A = [5,4,6,7,3;1,2,3,4,5;5,6,4,2,4;4,5,3,2,1];
% Get the number of rows and columns
[m,n] = size(A);
odd = 0;
for i = 1:m % number of rows
for j = 1:n % number of column
if (mod(A(i),2)~= 0) % if the element is not equal to zero, this is odd values
odd = odd + 1;
end
end
end
fprintf("There are %d odd values in the fence",odd);
There are 9 odd values
but in my code, it is shows There are 15 odd values in the fence.
How to improve this code?

Accepted Answer

Voss
Voss on 28 Mar 2022
if (mod(A(i,j),2)~= 0)
Use A(i,j) instead of A(i)
  4 Comments
Image Analyst
Image Analyst on 28 Mar 2022
And why do you say there are 9 values? My code below shows there are 10 values. Why do we disagree? Which one did I count that you say should not be counted?
Shuoze Xu
Shuoze Xu on 28 Mar 2022
There are 9 odd values showed on the pdf, I think it may a mistake

Sign in to comment.

More Answers (1)

Image Analyst
Image Analyst on 28 Mar 2022
A = [ 5, 4, 6, 7, 3 ; 1, 2, 3, 4, 5 ; 5, 6, 4, 2, 4 ; 4, 5, 3, 2, 1]
A = 4×5
5 4 6 7 3 1 2 3 4 5 5 6 4 2 4 4 5 3 2 1
numOddNumbers = nnz(rem(A, 2))
numOddNumbers = 10

Tags

Products


Release

R2021b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!