Problem with if function and decimal numers
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Good evening, i have a problem with this code:
a=1:0.1:2;
b=0.1;
for i=1:1:10
angoloutile(i)=a(i);
end
for j=1:1:10
integ = fix(angoloutile(j)) ;
fract = abs(angoloutile(j)- integ);
if fract == b
angoloutile(j)=angoloutile(j)+0.5
end
end
for k=1:1:10
angoloutile(k)
end
it doesn't take the IF function
if fract == b
but i'm sure that angoloutile(2) is 1.1 Thanks
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Accepted Answer
Image Analyst
on 13 Jan 2014
The problem was using fix instead of rounding. Try this where I use int32() to cast to the nearest integer. I also cleaned up your if to make it more efficient and reduce the number of if tests by a factor of 10.
a=1:0.1:2;
for i=1:1:10
angoloutile(i)=a(i);
end
for j=1:1:10
integ = fix(angoloutile(j));
fract = abs(angoloutile(j)- integ);
fract=fract*10;
deci=int32(fract);
fprintf('j = %d, angoloutile(j) = %f, integ = %d, fact = %f, deci = %d\n', ...
j, angoloutile(j), integ, fract, deci);
if deci == 1
angoloutile(j)=angoloutile(j)+0.5;
elseif deci == 2
angoloutile(j)=angoloutile(j)-0.08;
elseif deci == 3
angoloutile(j)=angoloutile(j)-0.12;
elseif deci == 4
angoloutile(j)=angoloutile(j)-0.16;
elseif deci == 5
angoloutile(j)=angoloutile(j)-0.20;
elseif deci == 6
angoloutile(j)=angoloutile(j)-0.24;
elseif deci == 7
angoloutile(j)=angoloutile(j)-0.28;
elseif deci == 8
angoloutile(j)=angoloutile(j)-0.32;
elseif deci == 9
angoloutile(j)=angoloutile(j)-0.36;
end
end
% Print to command window.
angoloutile
More Answers (1)
Amit
on 13 Jan 2014
The issue is very small difference in floating point numbers, like 1.00000 and 1.0000000001. There is negligible difference however they are not equal. You can do something like:
tol = 1e-6;
if (fract-b) < tol
This will work.
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