## grouping observations with specific characteristics

on 21 May 2012

### Geoff (view profile)

Hi all,

I have the following table in excel

```time	country	Location	price2
1/09	Austria	l1	12
2/09	Austria	l1	4
3/09	Austria	l1	2
1/09	Austria	l2	1
2/09	Austria	l2	23
3/09	Austria	l2	14
1/09	Germany	l1	100
2/09	Germany	l1	110
3/09	Germany	l1	120
1/09	Germany	l2	100
2/09	Germany	l2	110
3/09	Germany	l2	120
```

I want to obtain the following structure

1/09 Austria l1 12

1/09 Germany l1 100

` 2/09 	Austria	l1	4`

2/09 Germany l1 110

3/09 Austria l1 2

3/09 Germany l1 120

1/09 Austria l2 1

1/09 Germany l2 100

2/09 Austria l2 23

2/09 Germany l2 110

and so forth...

the first 3 varibles are string varibles.

Is there any "qick code" for this as i have a large matrix?

Oleg Komarov

### Oleg Komarov (view profile)

on 21 May 2012

This post has been duplicated on: http://www.mathworks.com/matlabcentral/answers/38955-conveting-a-string-of-variables-to-numbers

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### Geoff (view profile)

on 21 May 2012

You mean you want to sort by Location, then Time, then Country, then Price?

Before you go MatLabbing this... Would you consider that you can do this very easily in Excel?

Now, if you want to do it in MatLab, read all your data into an N-by-4 cell array (cell matrix, I guess), then call sortrows with your column order:

```sortedData = sortrows( origData, [3, 1, 2, 4] );
```

Staf

### Staf (view profile)

on 21 May 2012

Hi Geoff,
I want to gather together first all l1s that correspond to 1/09

then, i want to gather all l1s that correspond to 2/09

then, i want to gather all l1s that correspond to 3/09

then, i want to gather all l2s that correspond to `1/09

then, i want to gather all l2s that correspond to `2/09

then, i want to gather all l2s that correspond to `3/09

and so forth.....

Thanks

Geoff

### Geoff (view profile)

on 21 May 2012

Like I said. Sort by location and date (others are optional). If you can have I10 or more, or dates 10/09 or more, then you need to convert those... You could convert the 'I' column with something like this - might need syntax tweaks:

data{:,3} = cellfun( @(x) str2double(x(2:end)), {data{:,3}});

For the dates, you could pad a leading zero onto anything with only 4 characters.

Staf

### Staf (view profile)

on 22 May 2012

thank you Geoff!

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