Please help me with the code....

How to add space between each characters in matrix and those should be converted into ASCII...

For example taking string as input ie, matlabiseasy that has to be stored in matrix and remaining should be replaced with zeros as

m a t l
a b i s
e a s y
0 0 0 0

But when I execute this... there won't be space between 2 characters. ie,

matl
abis
easy
0000

As in C dont we have any fuction as /t for space... And how to convert the character to ASCII please help me with this code..

[per isakson]

Now I realize that &nbsp"..."&nbsp in&nbsp "execute this... there" &nbspis a reference to your previous question.

Answer 1

[per isakson]

A start

>> str = sprintf( '%c ', 'matlabiseasy' )
str =
m a t l a b i s e a s y 
>> str2 = permute( reshape( str, 8, [] ), [2,1] )
str2 =
m a t l 
a b i s 
e a s y 

>> double( str2 )
ans =
   109    32    97    32   116    32   108    32
    97    32    98    32   105    32   115    32
   101    32    97    32   115    32   121    32

Combining this with Walter's answer to your previous question

YourString = 'matlabiseasy_matlabiseasy_';
L = length( YourString );
N = ceil(sqrt(L));
A = char( '0' .* ones(N,N) );
A(1:L) = YourString;
str = sprintf( '%c ', A );
str = reshape( str, [2*N,N] );
permute( str, [2,1] )

outputs

ans =
m a t l a b 
i s e a s y 
_ m a t l a 
b i s e a s 
y _ 0 0 0 0 
0 0 0 0 0 0

In response to comment "Let me explain ..."

YourString = 'matlabiseasy_1234567890_abcdefghijklmnopqrstuvwxyz';
L = length( YourString );
e = ceil( log2(sqrt(L)) - log2(4) );
N = 4*2^e;
A = char( '0' .* ones(N,N) );
A(1:L) = YourString;
A = permute( A, [2,1] );
Nc = 4.*ones( 1, 2^e );
Rc = mat2cell( A, Nc, Nc )
r11 = Rc{1,1}

outputs

Rc = 
    [4x4 char]    [4x4 char]
    [4x4 char]    [4x4 char]
r11 =
matl
easy
4567
abcd

[radhika s gowda]

Sir.... I need it in matrix form... And that has to be each character should be converted to ASCII example is String : matlabiseasy as

    m a t l
    a b i s
    e a s y
    0 0 0 0

After this each letter should be converted to ASCII and stored in other matrix..

[Walter Roberson]

You have already been shown how to get the matrix form in http://uk.mathworks.com/matlabcentral/answers/266634-hi-my-question-is-how-to-store-string-in-matrix-form-and-the-matrix-should-me-nxn-matrix-and-it

Beyond that, a hint:

B(:,1:2:3) = A(:,1:2)

[per isakson]

• I added another step to my answer
• What do you mean by "convert the character to ASCII" ?
• How do I know how many zero, i.e. char(48), to concatenate at the end?
• "any function as /t for space" space, i.e. char(32)
• I didn't realize until now that this is a follow-up question

[Walter Roberson]

sprintf('%c\t%c\%c\t%c', 'matl')

[per isakson]

... and one step further

>> sprintf('%c\t%c\t%c\t%c\n', 'matlabiseasy')
ans =
m  a  t  l
a  b  i  s
e  a  s  y

[Image Analyst]

I think he wanted a square matrix with any elements beyond the end of the string (numel(str)) and the end of the square array (columns^2) to be assigned a value of '0'.

[Walter Roberson]

No, the poster now requires horizontal spaces between the letters but not vertical spaces, so they are not looking for a square matrix result now.

[radhika s gowda]

Sir... Let me explain u my problem correctly I want to take input as string and that has to be stored in 4x4 8x8 or 16x16 only and if string length is lesser than 16 in case of 4x4 matrix then remaining should be filled with zeros.. I need only 4x4 8x8 or 16x16 matrix only because in further work I need matrix to be divided into 4 equal parts so so by 3x3 or 6x6 cant be used.... Socan u help me in solving this problem

[Walter Roberson]

The version that runs all of the letters together on one line is the solution. In MATLAB, a string is the same thing as a row of characters, so if you display a character array then it is going to display as strings. That does not mean that everything in the row has been stored in the first element of the row.

If you really want to the output could instead be made a cell array of strings, one character oer cell. That would make it easier to see that there is only one character stored in each position, but it does make it more difficult to work with the characters afterwards.

[per isakson]

• "... input as string ... to be stored in 4x4 8x8 or 16x16 [matrix] ... [padded] with zeros"
• "4x4, 8x8 or 16x16" &nbsp thus I assume that 12x12 isn't allowed.
• "... need matrix to be divided into 4 equal parts ..." &nbsp I understand that the size of the resulting matrix shall be &nbsp<4*2^k x 4*2^k>&nbsp where k is a whole number.
• "equal parts" &nbsp are <4x4> character arrays
• You don't mention the "delimiter", tab or space, in your comment.

I propose

• See Fundamental MATLAB Classes and decide what "data type" you want for the output
• Store the result as a square cell array of&nbsp<4x4> character arrays. See answer above.

Answer 2

[Image Analyst]

I think this will do what you want:

str = 'matlabiseasy'
len = length(str);
fprintf('Original length of str = %d\n', len);
% Compute how many rows.
numRows = ceil(sqrt(len))
% However it's not a multiple of 4 yet.
% Make it a multiple of 4
numRows = ceil(numRows / 4) * 4
% Add zeros
str = [str, zeros(1, numRows^2-len)+'0']
fprintf('Now length of str = %d\n', length(str));
% Reshape into a square array
out = reshape(str', numRows, numRows)'

I've tested it with strings of different lengths, and the output is always a square matrix where the number of rows and columns is a multiple of 4 like you wanted. Note that it may not look "square" when printed out in the command window but it is. When echoing to the command window, there is less room between characters on the same line, than between different lines, so it will look taller than wide, but it is still square regardless of how it looks. If you really want spaces, you can do that with fprintf() rather than just let MATLAB decide on it's own how to display it.

Now, can you tell us why you wanted this funny array?

[Walter Roberson]

12 is not allowed as a length, only powers of 2.

The poster is working on an assignment.

And I think what the poster wants to see is the equivalent of

num2cell(out)

I wouldn't recommend that for computation, but it is an option.

[Image Analyst]

OK, right. It would be easy to modify

numRows = ceil(numRows / 4) * 4

to make it be a power of 2 instead of a multiple of 4. I didn't see the poster say it's a homework problem and they didn't tag it as homework, but since it may be an assignment, I'll leave that modification up to them.