vector median filter

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Yogesh Joshi
Yogesh Joshi on 28 Dec 2011
is there any function in matlab for vector median filter or vector directional filter? plz help.
  2 Comments
Walter Roberson
Walter Roberson on 28 Dec 2011
Is there a difference between "vector median filter" and "median filter applied to a vector" ?
Yogesh Joshi
Yogesh Joshi on 28 Dec 2011
yes, vector median filter is used for color image enhancement.

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Accepted Answer

Chandra Kurniawan
Chandra Kurniawan on 28 Dec 2011
for 1D median filtering, Matlab has command medfilt1
Eq:
medfilt1([4 3 5 2 8 9 1],3)
ans =
3 4 3 5 8 8 1
  4 Comments
Walter Roberson
Walter Roberson on 28 Dec 2011
color images are 3D matrices.
Chandra Kurniawan
Chandra Kurniawan on 29 Dec 2011
Yes, I meant 3D matrix
That right function medfilt2 works on 2D image array.
Then, you can use the same function to filter rgb <color> image plane by plane.
I mean you need to apply this to red plane, green plane, blue plane one-by-one.
Here I give you sample code :
I = imread('peppers.png');
J = imnoise(I,'salt & pepper');
imshow(J);
K(:,:,1) = medfilt2(J(:,:,1));
K(:,:,2) = medfilt2(J(:,:,2));
K(:,:,3) = medfilt2(J(:,:,3));
figure, imshow(K);

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More Answers (2)

Image Analyst
Image Analyst on 28 Dec 2011
Whether applying medfilt2() to each color plane independently (such as my code here: http://www.mathworks.com/matlabcentral/answers/16350-how-to-remove-pixels-in-an-image) is an improvement is something you'll have to decide as this can give color artifacts that can make it worse. Maybe you want to convert to HSV and just use medfilt2 on the V channel. Or you can do more sophisticated, smarter things like median filtering the image (somehow) and then replace only SOME of the pixels - the "bad" ones, which you've identified somehow - rather than all of them.

Yogesh Joshi
Yogesh Joshi on 2 Jan 2012
I think using medfilt2 for each color plane will not give good results,instead treat each pixel as vector and use vector median filter algorithm
  1 Comment
Image Analyst
Image Analyst on 2 Jan 2012
OK, what's the algorithm for that?

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