Applications involving electrostatics include high voltage apparatus, electronic devices, and capacitors. The "statics" implies that the time rate of change is slow, and that wavelengths are very large compared to the size of the domain of interest. In electrostatics, the electrostatic scalar potential V is related to the electric field E by E = –∇V and, using one of Maxwell's equations, ∇ · D = ρ and the relationship D = εE, we arrive at the Poisson equation
–∇ · (ε∇V) = ρ,
where ε is the coefficient of dielectricity and ρ is the space charge density.
Note ε should really be written as ε ε_{0}, where ε_{0} is the coefficient of dielectricity or permittivity of vacuum (8.854 · 10^{-12 }farad/meter) and ε is the relative coefficient of dielectricity that varies among different dielectrics (1.00059 in air, 2.24 in transformer oil, etc.). |
Using the Partial Differential Equation Toolbox™ electrostatics application mode, you can solve electrostatic problems modeled by the preceding equation.
The PDE Specification dialog box contains entries for ε and ρ.
The boundary conditions for electrostatic problems can be of Dirichlet or Neumann type. For Dirichlet conditions, the electrostatic potential V is specified on the boundary. For Neumann conditions, the surface charge n · (ε∇V ) is specified on the boundary.
For visualization of the solution to an electrostatic problem, the plot selections include the electrostatic potential V, the electric field E, and the electric displacement field D.
For a more in-depth discussion of problems in electrostatics, see Popovic, Branko D., Introductory Engineering Electromagnetics, Addison-Wesley, Reading, MA, 1971.
Let us consider the problem of determining the electrostatic potential in an air-filled quadratic "frame," bounded by a square with side length of 0.2 in the center and by outer limits with side length of 0.5. At the inner boundary, the electrostatic potential is 1000V. At the outer boundary, the electrostatic potential is 0V. There is no charge in the domain. This leads to the problem of solving the Laplace equation
ΔV = 0
with the Dirichlet boundary conditions V = 1000 at the inner boundary, and V = 0 at the outer boundary.
After setting the application mode to Electrostatics, the 2-D area is most easily drawn by first drawing a square with sides of length 0.2 (use the Snap option and adjust the grid spacing if necessary). Then draw another square with sides of length 0.5 using the same center position. The 2-D domain is then simply SQ2-SQ1, if the first square is named SQ1 and the second square is named SQ2. Enter the expression into the Set formula edit box, and proceed to define the boundary conditions. Use Shift+click to select all the inner boundaries. Then double-click an inner boundary and enter 1000 as the Dirichlet boundary condition for the inner boundaries.
Next, open the PDE Specification dialog box, and enter 0
into
the space charge density (rho
) edit field. The
coefficient of dielectricity can be left at 1, since it does not affect
the result as long as it is constant.
Initialize the mesh, and click the = button to solve the equation. Using the adaptive mode, you can improve the accuracy of the solution by refining the mesh close to the reentrant corners where the gradients are steep. For example, use the triangle selection method picking the worst triangles and set the maximum number of triangles to 500. Add one uniform mesh refinement by clicking the Refine button once. Finally turn adaptive mode off, and click the = button once more.
To look at the equipotential lines, select a contour plot from
the Plot Selection dialog box. To display equipotential lines at every
100th volt, enter 0:100:1000
into the Contour
plot levels edit box.
Equipotential Lines in Air-Filled Frame